Question Detail
Question
A parallel plate air capacitor with no dielectric between the plates is connected to the constant voltage source. How would capacitance and charge change if dielectric of dielectric constant K=2 is inserted between the plates. Co and Qo are the capacitance and charge of the capacitor before the introduction of the dielectric.
Correct Answer
Option D is the correct answer.
Detailed Explanation
When a dielectric material with dielectric constant K is inserted into a capacitor, the new capacitance C becomes K times the original capacitance Co. So, C = K * Co. Given K=2, C = 2 * Co.Since the capacitor remains connected to a constant voltage source, the voltage (V) across the plates remains the same.The charge (Q) on a capacitor is given by Q = C * V. So, the new charge Q = C * V = (K * Co) * V = K * (Co * V) = K * Qo.Given K=2, Q = 2 * Qo.Therefore, C = 2Co and Q = 2Qo.
Hint
Remember how a dielectric affects capacitance. Also, consider that the voltage remains constant because it's connected to a constant voltage source.