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The force on a current-carrying conductor in a magnetic field is given by F = BILsin(θ).Given: Current I = 3 A, Magnetic field B = 0.5 T."A metre length conductor" implies total length L_total = 1 m."a quarter if its length" suggests the effective length (L) experiencing the force is L_total / 4 = 1 m / 4 = 0.25 m."perpendicular to a magnetic field" means θ = 90°, so sin(θ) = 1.F = (0.5 T) * (3 A) * (0.25 m) * sin(90°)F = 0.5 * 3 * 0.25 * 1 = 0.375 N.