Question Detail

MTH 102 PHY 102 Past Questions Objective Question

Question

A galvanometer has spring constant 'k', a magnetic field 'B' and deflection angle θ. The coil has N turns and an area A. Which of the following is the condition for equilibrium of the coil when current I flows in the galvanometer?
Options
A KB = θIAN
B Kθ = BIAN
Correct Answer
C BI = KθAN
D Kθ = BA/IN
Correct Answer

Option B is the correct answer.

Detailed Explanation

In a galvanometer, the magnetic torque experienced by the coil is balanced by the restoring torque of the spring. The magnetic torque (τ_magnetic) is given by τmagnetic = N I A B sin(α), where α is the angle between the magnetic field and the normal to the coil. For an ideal galvanometer, often a radial magnetic field is assumed such that sin(α) ≈ 1 or it is directly proportional to θ.The restoring torque (τspring) of the spring is given by τspring = kθ, where k is the spring constant and θ is the deflection angle.At equilibrium, τmagnetic = τspring. Therefore, N I A B = kθ (or Kθ = BIAN, using K for the spring constant as in the option).

Hint

Equilibrium in a galvanometer means the magnetic torque is balanced by the restoring torque from the spring.

Question Info