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PHY 102 Test Compilation PHY 102 14 Objective Question
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Question

Which of the following is the correct relationship between the PEAK value and the R.M.S. value of an alternating signal?
Options
A peak = r.m.s. x √2
Correct Answer
B r.m.s. = peak x √2
C peak = r.m.s./√2
D peak = √2/r.m.s.
Correct Answer

Option A is the correct answer.

Detailed Explanation

For a sinusoidal alternating current or voltage, the Root Mean Square (RMS) value is related to the peak value (V_peak or I_peak) by the equation: RMS = Peak / √2. Rearranging this, Peak = RMS × √2.

Hint

The RMS value is a measure of the effective value of an AC signal, and it is always less than the peak value for a sine wave.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 14
Type: Objective
Difficulty: Not specified
Question 992 of 1819
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