Question Detail

PHY 102 Test Compilation PHY 102 14 Objective Question

Question

Calculate the flux through a coil loop of area 0.45m2 when its plane is inclined at an angle of 60° to a magnetic field of 1.15T.
Options
A 0.17 Wb
B 0.45 Wb
Correct Answer
C 4.06 Wb
D 5.73 Wb
Correct Answer

Option B is the correct answer.

Detailed Explanation

Magnetic flux (Φ) is given by Φ = B × A × cos(θ), where B is the magnetic field strength, A is the area, and θ is the angle between the magnetic field lines and the normal to the surface.Given: B = 1.15 T, A = 0.45 m2. The plane is inclined at 60° to the magnetic field, so the angle with the normal is θ = 90° - 60° = 30°.Φ = 1.15 T × 0.45 m2 × cos(30°)Φ = 0.5175 × (√3 / 2)Φ = 0.5175 × 0.8660Φ ≈ 0.449 Wb.The closest option is 0.45 Wb. (Note: The unit 'wb/m2' in the options is a typo, it should be 'Wb' for magnetic flux).

Hint

Pay close attention to the angle definition: is it with the plane or with the normal to the plane?

Question Info