Question Detail

PHY 102 Test Compilation PHY 102 14 Objective Question

Question

Calculate the flux through a coil loop of area 0.45m2 when its plane is inclined at an angle of 60° to a magnetic field of 1.15T
Options
A 0.17wb/m<sup>2</sup>
B 0.45wb/m<sup>2</sup>
Correct Answer
C 4.06wb/m<sup>2</sup>
D 5.73wb/m<sup>2</sup>
Correct Answer

Option B is the correct answer.

Detailed Explanation

The magnetic flux (Φ) through a coil is given by the formula Φ = B * A * cos(θ), where B is the magnetic field strength, A is the area of the coil, and θ is the angle between the magnetic field vector and the area vector (which is normal to the plane of the coil).Given: B = 1.15 T, A = 0.45 m2. The plane is inclined at 60° to the magnetic field, so the angle θ between the normal to the plane and the magnetic field is 90° - 60° = 30°.Φ = 1.15 T × 0.45 m2 × cos(30°)Φ ≈ 1.15 × 0.45 × 0.866Φ ≈ 0.448 Wb.Among the options, 0.45 (assuming Wb units instead of Wb/m2 which is an incorrect unit for flux) is the closest numerical value.

Hint

Remember that magnetic flux is B.A cos(θ), where θ is the angle between the magnetic field and the normal to the area. Also, pay attention to the units requested for flux (Weber, Wb).

Question Info