Question Detail
Question
The electric field intensity of 100 N/C is applied on circular surface area at an angle of 60° to the surface. What is the flux intensity in Nm2/C through the circular surface of radius 7m?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The electric flux (Φ) through a surface is given by the formula Φ = E * A * cos(θ), where E is the electric field intensity, A is the area of the surface, and θ is the angle between the electric field vector and the area vector (normal to the surface).Given: E = 100 N/C. Radius r = 7 m.Area A = πr2 = π(7 m)2 = 49π m2.The electric field is applied at an angle of 60° to the surface. Therefore, the angle θ between the electric field and the normal to the surface is 90° - 60° = 30°.Using the approximation π ≈ 22/7 for the calculation:A = (22/7) × (7 m)2 = 154 m2.Now, calculate the flux:Φ = 100 N/C × 154 m2 × cos(30°)Φ = 100 × 154 × (√3 / 2) Nm2/CΦ = 7700√3 Nm2/C.
Hint
Remember that the angle in the flux formula (Φ = EAcosθ) is between the electric field and the normal to the surface. Use π ≈ 22/7 if the options suggest such an approximation.