Question Detail
Question
A parallel plate capacitor has an area of 2000 cm², and the plates are 1 cm apart. The original potential difference between them, V₀, is 3000 volts, and it decreases to 1000 volts when a sheet of dielectric is inserted between the plates. Compute the electric intensity E after insertion of the dielectric.
Correct Answer
Option D is the correct answer.
Detailed Explanation
The electric intensity (electric field) E in a parallel plate capacitor is given by E = V/d, where V is the potential difference between the plates and d is the distance between them.After the dielectric is inserted, the potential difference decreases to V = 1000 volts.The distance between the plates is d = 1 cm = 0.01 m.E = V/d = 1000 V / 0.01 m = 100000 V/m = 1.0 × 10⁵ V/m.
Hint
The electric field inside a parallel plate capacitor is simply the voltage across the plates divided by their separation distance.