Question Detail
Question
What must be the charge (sign and magnitude) of a particle of mass 5 g for it to remain stationary when placed in a downward-directed electric field of magnitude 800 N/C?
Correct Answer
Option B is the correct answer.
Detailed Explanation
For the particle to remain stationary, the upward electric force must balance the downward gravitational force. Gravitational force: F_g = mg Electric force: F_e = qE Given: mass m = 5 g = 0.005 kg, Electric field E = 800 N/C, acceleration due to gravity g = 9.8 m/s². Equating forces: qE = mg q = mg/E = (0.005 kg * 9.8 m/s²) / 800 N/C = 0.049 / 800 C = 0.00006125 C = 61.25 µC. Since the gravitational force is downward and the electric field is downward, the electric force must be upward to keep the particle stationary. For the electric force (F_e = qE) to be upward when E is downward, the charge 'q' must be negative. Therefore, the charge is -61.25 µC, which is approximately -61.3 µC. (Note: The options in the original image contain a typo, using 'µF' instead of 'µC'.)
Hint
For an object to remain stationary in an electric field, the electric force must exactly balance the gravitational force. Remember to consider the direction of the electric field and the sign of the charge.