Question Detail

Electric flux (Φ) is given by Φ = E ⋅ A, where E is the electric field and A is the area vector. Maximum electric flux occurs when the electric field is perpendicular to the surface, meaning it's parallel to the area vector (cosθ = 1).For a cylindrical surface in a uniform electric field, the maximum flux would typically pass through one of the circular caps (if the field is normal to the cap) or the curved surface (if the field is parallel to the axis of the cylinder, and thus normal to the area vector of the curved surface, which is tangential). Assuming the 'maximum flux' refers to the flux through one of the circular ends, as this is a common scenario for cylindrical Gauss surfaces.Radius r = 5 cm = 0.05 m.Area of one circular cap (A_cap) = πr² = π * (0.05 m)² = π * 0.0025 m² ≈ 0.007854 m².Electric field E = 250 N/C.Maximum flux Φ_max = E * A_cap = 250 N/C * 0.007854 m² ≈ 1.9635 Nm²/C.The correct units for electric flux are Nm²/C (or Vm). Option B has the correct value and units.