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PHY 102 Test Compilation PHY 102 17 Objective Question
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Question

A cylindrical surface of radius 5 cm and height 2.5 cm is placed in a uniform electric field of 250 N/C. Find the maximum electric flux that can pass through the surface.
Options
A 1.963 C<sup>-2</sup>.N<sup>-1</sup>.m<sup>-2</sup>
B 1.963 Nm<sup>2</sup>.C<sup>-1</sup>
Correct Answer
C 0.982 Nm<sup>2</sup>.C<sup>-1</sup>
D 0.982 C<sup>-2</sup>.N<sup>-1</sup>.m<sup>-2</sup>
Correct Answer

Option B is the correct answer.

Detailed Explanation

The maximum electric flux through a surface in a uniform electric field occurs when the electric field lines are perpendicular to the surface. For a cylindrical surface, this maximum flux will occur through one of its circular end caps (assuming the field is parallel to the cylinder's axis).Radius (r) = 5 cm = 0.05 mElectric Field (E) = 250 N/CArea of one circular end cap (A) = πr2 = π(0.05 m)2 = π(0.0025 m2) ≈ 0.007854 m2.Electric Flux (Φ) = E ⋅ A = (250 N/C) ⋅ (0.007854 m2) ≈ 1.9635 Nm2/C.Option B has the correct value and units for electric flux.

Hint

Electric flux is maximized when the electric field is perpendicular to the area. For a cylinder, consider the area of its end caps.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 17
Type: Objective
Difficulty: Not specified
Question 1109 of 1819
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