Question Detail

Electric flux (Φ) through a surface is given by Φ = E ⋅ A = EA cos(θ), where E is the electric field strength, A is the area, and θ is the angle between the electric field vector and the area vector (normal to the surface).Maximum flux occurs when θ = 0°, so cos(θ) = 1, and Φmax = EA.For a cylindrical surface in a uniform electric field, the maximum flux occurs when the electric field is perpendicular to the curved surface area, meaning it passes through the 'sides' of the cylinder.Radius (r) = 5 cm = 0.05 mHeight (h) = 2.5 cm = 0.025 mElectric field (E) = 250 N/CCurved Surface Area (A) = 2πrh = 2π(0.05 m)(0.025 m) = 0.00785398 m2Φmax = (250 N/C) * (0.00785398 m2) = 1.963495 Nm2/C.The unit Nm2C-1 is equivalent to Nm2/C.