Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Find dy/dx if 3x²y + xy² = 5
Options
A dy/dx = (y² + 6xy) / (3x² + 2xy)
B dy/dx = -(y² + 6xy) / (3x² + 2xy)
Correct Answer
C dy/dx = -(y² + 6xy) / (3x² - 2xy)
D dy/dx = (y² - 6xy) / (3x² - 2xy)
Correct Answer

Option B is the correct answer.

Detailed Explanation

We use implicit differentiation. Differentiate each term with respect to x:d/dx (3x²y) + d/dx (xy²) = d/dx (5)Apply the product rule for the first two terms:(6xy + 3x² dy/dx) + (y² + x(2y dy/dx)) = 06xy + 3x² dy/dx + y² + 2xy dy/dx = 0Group terms containing dy/dx on one side and the remaining terms on the other:(3x² + 2xy) dy/dx = -6xy - y²Factor out dy/dx and solve:dy/dx = -(6xy + y²) / (3x² + 2xy).This matches option B.

Hint

Apply implicit differentiation. Remember to use the product rule for terms like 3x²y and xy². Collect all terms with dy/dx on one side of the equation.

Question Info