Question Detail

To evaluate the integral ∫ 3x²e^(x³) dx, we use a substitution (u-substitution).Let u = x³.Then, the differential du = (d/dx(x³)) dx = 3x² dx.Substitute u and du into the integral:∫ e^u duThe integral of e^u with respect to u is e^u.So, ∫ e^u du = e^u + C.Finally, substitute back u = x³:e^(x³) + C.Thus, option B is correct.