Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Evaluate ∫ Cos3 x dx.
Options
A sinx - <sup>1</sup>&frasl;<sub>3</sub> sin<sup>3</sup> x + C
Correct Answer
B cosx + <sup>1</sup>&frasl;<sub>3</sub> cos<sup>3</sup> x + C
C secx - <sup>1</sup>&frasl;<sub>3</sub> sec<sup>3</sup> x + C
D tanx - <sup>1</sup>&frasl;<sub>3</sub> tan<sup>3</sup> x + C
Correct Answer

Option A is the correct answer.

Detailed Explanation

To integrate odd powers of cosine, we use the identity cos2x = 1 - sin2x.∫ cos3x dx = ∫ cos2x * cosx dx= ∫ (1 - sin2x) cosx dxNow, use u-substitution. Let u = sinx.Then, du = d/dx(sinx) dx = cosx dx.Substitute u and du into the integral:= ∫ (1 - u2) duIntegrate with respect to u:= u - u3⁄3 + CSubstitute back u = sinx:= sinx - sin3x⁄3 + C.This matches option A.

Hint

Use the trigonometric identity cos2x = 1 - sin2x to rewrite cos3x. Then, use u-substitution with u = sinx.

Question Info