Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Find \( \frac{dy}{dx} \) if \( 3x^2 y + xy^2 = 5 \)
Options
A \( \frac{dy}{dx} = \frac{y^2+6xy}{3x^2+2xy} \)
B \( \frac{dy}{dx} = -\frac{y^2+6xy}{3x^2+2xy} \)
Correct Answer
C \( \frac{dy}{dx} = -\frac{y^2+6xy}{3x^2-2xy} \)
D \( \frac{dy}{dx} = \frac{y^2-6xy}{3x^2-2xy} \)
Correct Answer

Option B is the correct answer.

Detailed Explanation

Differentiate implicitly with respect to ( x ):( \frac{d}{dx}(3x^2 y) + \frac{d}{dx}(xy^2) = \frac{d}{dx}(5) )Using the product rule for each term on the left:( (6xy + 3x^2 \frac{dy}{dx}) + (y^2 + x \cdot 2y \frac{dy}{dx}) = 0 )( 6xy + 3x^2 \frac{dy}{dx} + y^2 + 2xy \frac{dy}{dx} = 0 )Group terms containing ( \frac{dy}{dx} ):( (3x^2 + 2xy) \frac{dy}{dx} = -6xy - y^2 )Solve for ( \frac{dy}{dx} ):( \frac{dy}{dx} = \frac{-6xy - y^2}{3x^2 + 2xy} = -\frac{y^2 + 6xy}{3x^2 + 2xy} )This matches option B.

Hint

Apply implicit differentiation. Remember to use the product rule for terms involving both \( x \) and \( y \), and the chain rule for \( y \) terms.

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