Question Detail
Question
In Young's double-slit experiment, if light of frequency 6.0 x 1014 Hz is used, slits are separated by 0.2 mm, and the screen is 1m from the slits, what is the fringe width? (Assume speed of light c = 3.0 x 108 m/s)
Correct Answer
Option C is the correct answer.
Detailed Explanation
First, calculate the wavelength: λ = c/f = (3.0 × 108 m/s) / (6.0 × 1014 Hz) = 0.5 × 10-6 m = 500 nm. Given: d = 0.2 mm = 0.2 × 10-3 m, x = 1 m. Fringe width (separation between consecutive bright fringes, Δy) = λx/d. Δy = (0.5 × 10-6 m × 1 m) / (0.2 × 10-3 m) Δy = (0.5 × 10-6) / (0.2 × 10-3) = 2.5 × 10-3 m = 2.5 mm.
Hint
First, calculate the wavelength from the given frequency and speed of light. Then use the formula for fringe width, which is the separation between adjacent bright (or dark) fringes.