Question Detail
Question
For a normal eye, an image is formed on the retina at a distance of 1.5 cm from the lens. If a 25 m tall tree forms a 1.0 cm tall image on the retina, how far away from the eye is the tree?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The magnification (M) is given by the ratio of image height (h_i) to object height (h_o), and also by the ratio of image distance (v) to object distance (u). M = h_i / h_o = v / u. Given h_i = 1.0 cm = 0.01 m, h_o = 25 m, and v = 1.5 cm = 0.015 m. So, 0.01 m / 25 m = 0.015 m / u. Solving for u: u = (0.015 m * 25 m) / 0.01 m = 37.5 meters.
Hint
Use the magnification formula that relates image and object heights to their respective distances from the lens. Ensure all units are consistent (e.g., convert centimeters to meters).