Question Detail
Question
Find the potential difference required to give a helium nucleus (q = 3.2×10⁻¹⁹C) a kinetic energy of 4.8×10⁷eV, where 1eV = 1.6×10⁻¹⁹J.
Correct Answer
Option D is the correct answer.
Detailed Explanation
KE in joules = 4.8×10⁷ × 1.6×10⁻¹⁹ = 7.68×10⁻¹²J, and V = KE/q = 7.68×10⁻¹²/3.2×10⁻¹⁹ ≈ 2.4×10⁷V.
Hint
Convert the kinetic energy from eV to joules first, then use V = KE/q.