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PHY 102 Test Compilation PHY 102 18 Objective Question
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Question

An electron moves in a magnetic field in a direction inclined at 60° to the plane of the magnetic field with a velocity of 4.0×10⁶m/s. If the magnetic field strength is 0.04T, calculate the force on the electron.
Options
A 1.0 × 10⁻¹⁴N
B 2.2 × 10⁻¹⁵N
Correct Answer
C 1.4 × 10⁻¹⁵N
D 1.5 × 10⁻¹⁴N
Correct Answer

Option B is the correct answer.

Detailed Explanation

Using F = qvBsinθ with the appropriate angle between velocity and field, and substituting the electron's charge, velocity, and field strength, gives a force of about 2.2×10⁻¹⁵N.

Hint

Be careful whether the given 60° is measured from the field itself or from the plane of the field before applying F = qvBsinθ.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 18
Type: Objective
Difficulty: Not specified
Question 1164 of 1819
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