Question Detail
Question
Two capacitors each of 6F and 3F are connected in series with a potential difference of 12V. Find the p.d. across the 6F capacitor.
Correct Answer
Option D is the correct answer.
Detailed Explanation
C_eq = (6×3)/(6+3) = 2F, so total charge Q = C_eq×V = 2×12 = 24C. Since series capacitors share the same charge, V across the 6F capacitor = Q/6 = 4V.
Hint
Find the equivalent series capacitance to get the shared charge Q, then divide by each individual capacitance to get its voltage.