Question Detail
Question
Find the electric field intensity at a distance of 20cm from a charge of 2nC.
Correct Answer
Option D is the correct answer.
Detailed Explanation
E = kQ/r² = (8.99×10⁹)(2×10⁻⁹)/(0.2)² ≈ 450 N/C.
Hint
Apply E = kQ/r² directly with the given charge and distance.