Question Detail
Question
What change in potential energy does a 4μC charge experience when it moves between two points that differ in potential by 80V?
Correct Answer
Option A is the correct answer.
Detailed Explanation
The change in energy is W = qΔV = (4×10⁻⁶)(80) = 3.2×10⁻⁴J.
Hint
Apply W = qΔV directly with the given charge and potential difference.