Question Detail
Question
The electric field everywhere on the surface of a hollow sphere of radius 6cm is measured to be 2.9×10⁴N/C. What is the charge enclosed by the surface?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Using Q = Er²/k = (2.9×10⁴)(0.06)²/(8.99×10⁹) ≈ 1.16×10⁻⁸C ≈ 0.012μC.
Hint
Rearrange the point-charge field formula E = kQ/r² to solve for Q using the sphere's radius.