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PHY 102 Test Compilation PHY 102 20 Objective Question
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Question

Two charges of equal magnitude exert an attractive force of 6 x 10-3 N on each other. If the magnitude of each charge is 3.0 uC, how far apart are the charges?
Options
A 3.67 m
Correct Answer
B 9.50 m
C 11.50 m
D 12.50 m
Correct Answer

Option A is the correct answer.

Detailed Explanation

Use Coulomb's law F = kq1q2/r2, so r = sqrt(k q1 q2 / F). r = sqrt[(9x109)(3x10-6)(3x10-6) / (6x10-3)] = sqrt[(9x109 x 9x10-12) / (6x10-3)] = sqrt[0.081 / 0.006] = sqrt(13.5) = 3.67 m.

Hint

Use Coulomb's law F = kq1q2/r2, so r = sqrt(k q1 q2 / F).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 20
Type: Objective
Difficulty: Not specified
Question 1226 of 1819
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