Question Detail
Question
The force between two charges in vacuum is 0.24 N. If the medium is suddenly changed to one with relative permittivity of 2, all other conditions remaining unchanged, determine the force between these charges.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Force in a medium: F_medium = F_vacuum/eps_r = 0.24/2 = 0.12 N (force decreases because the dielectric medium partially cancels the field between the charges).
Hint
Force in a medium: F_medium = F_vacuum/eps_r = 0.24/2 = 0.12 N (force decreases because the dielectric medium partially cancels the field between the charges).