Question Detail
Question
A small object carrying a charge of 5x10-9 C experiences a downward force of 20x10-9 N when placed at a certain point in an electric field. What is the electric field at the point?
Correct Answer
Option C is the correct answer.
Detailed Explanation
E = F/q = (20x10-9)/(5x10-9) = 4.00 N/C.
Hint
E = F/q = (20x10-9)/(5x10-9) = 4.00 N/C.