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PHY 102 Test Compilation PHY 102 20 Objective Question
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Question

Determine the surface charge density on a sphere with radius R = 5 cm and charge Q = 1 uC uniformly distributed on the surface of the sphere.
Options
A 3.18 x 10-5 C/m2
Correct Answer
B 31.8 x 10-4 C/m2
C 3.2 x 10-4 C/m2
D 6.4 x 10-4 C/m2
Correct Answer

Option A is the correct answer.

Detailed Explanation

Surface area of sphere A = 4piR2 = 4pi(0.05)2 = 4pi0.0025 = 0.0314 m2. sigma = Q/A = (1x10-6)/(0.0314) = 3.18x10-5 C/m2.

Hint

Surface area of sphere A = 4*pi*R2 = 4*pi*(0.05)2 = 4*pi*0.0025 = 0.0314 m2.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 20
Type: Objective
Difficulty: Not specified
Question 1248 of 1819
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