Question Detail
Question
The electric field 2.0 m from a point charge has a magnitude of 8.0x104 N/C. What is the strength of the electric field at a distance of 4.0 m?
Correct Answer
Option A is the correct answer.
Detailed Explanation
E is proportional to 1/r2. Doubling the distance (2m -> 4m) reduces E by a factor of 22 = 4. New E = (8.0x104)/4 = 2.0x104 N/C.
Hint
E is proportional to 1/r2.