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PHY 102 Test Compilation PHY 102 21 Objective Question
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Question

Determine the force between two protons placed at a distance 1 um apart.
Options
A 2.3 x 10-13 N, attraction
B 2.3 x 10-13 N, repulsion
C 2.3 x 10-16 N, attraction
D 2.3 x 10-16 N, repulsion
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

F = k e2/r2 = (9x109)(1.6x10-19)2/(1x10-6)2 = (9x109)(2.56x10-38)/(1x10-12) = 2.304x10-16 N. Protons are both positively charged, so the force is REPULSIVE.

Hint

F = k e2/r2 = (9x109)(1.6x10-19)2/(1x10-6)2 = (9x109)(2.56x10-38)/(1x10-12) = 2.304x10-16 N.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 21
Type: Objective
Difficulty: Not specified
Question 1284 of 1819
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