Question Detail
Question
A point charge, -30 uC, is placed at the origin of the coordinates. Find the electric field at a point 50cm along the x-direction.
Correct Answer
Option C is the correct answer.
Detailed Explanation
E = kQ/r2 = (9x109)(30x10-6)/(0.5)2 = 270000/0.25 = 1.08x106 N/C = 1.08 MN/C. Since the charge is negative, the field points TOWARD the origin (i.e. in the -x direction at this point), giving E = -1.08 MN/C.
Hint
E = kQ/r2 = (9x109)(30x10-6)/(0.5)2 = 270000/0.25 = 1.08x106 N/C = 1.08 MN/C.