Question Detail

PHY 102 PHY 102 Past Questions Objective Question
Take CBT

Question

An electron is positioned in an electric field. The force on the electron due to the electric field is equal to the force of gravity on the electron. What is the magnitude of this electric field?
Options
A 8.93 x 10-30 N/C
B 5.69 x 10-11 N/C
Correct Answer
C 5.58 x 10-9 N/C
D 1.44 x 10-9 N/C
Correct Answer

Option B is the correct answer.

Detailed Explanation

For equilibrium: qE = mg => E = mg/q. E = (9.11x10-31 kg)(9.8 m/s2)/(1.6x10-19 C) = (8.93x10-30)/(1.6x10-19) = 5.58x10-11 N/C ~ 5.69x10-11 N/C.

Hint

For equilibrium: qE = mg => E = mg/q.

Question Info

Course: PHY 102
Topic: PHY 102 Past Questions
Type: Objective
Difficulty: Not specified
Question 1293 of 1820
Previous Course Details Next