Question Detail
Question
Find the electric field at a point 0.2 m from a charge of 20 uC. What force will the field exert on a charge of 10 uC placed at that point?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Step 1 - find E: E = kQ/r2 = (9x109)(20x10-6)/(0.2)2 = 180,000/0.04 = 4.5x106 N/C. Step 2 - find F on the second charge: F = qE = (10x10-6)(4.5x106) = 45.0 N.
Hint
Step 1 - find E: E = kQ/r2 = (9x109)(20x10-6)/(0.2)2 = 180,000/0.04 = 4.5x106 N/C.