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PHY 102 PHY 102 Past Questions Objective Question

Question

What is the magnitude of an electric field in which the force on an electron equals the weight of the electron? (m = 9.11x10-31 kg, e = 1.6x10-19 C)
Options
A 2.00 x 10-11 N/C
B 4.65 x 10-11 N/C
C 5.00 x 10-11 N/C
D 5.58 x 10-11 N/C
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Set electric force = weight: qE = mg E = mg/q = (9.11x10-31)(9.8)/(1.6x10-19) = (8.93x10-30)/(1.6x10-19) = 5.58x10-11 N/C.

Hint

Set electric force = weight: qE = mg E = mg/q = (9.11x10-31)(9.8)/(1.6x10-19) = (8.93x10-30)/(1.6x10-19) = 5.58x10-11 N/C.

Question Info