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PHY 102 Test Compilation PHY 102 21 Objective Question

What is the magnitude of an electric field in which the force on an electron equals the weight of the electron? (m = 9.11x10-31 kg, e = 1.6x10-19 C)

A 2.00 x 10-11 N/C

B 4.65 x 10-11 N/C

C 5.00 x 10-11 N/C

D 5.58 x 10-11 N/C

Correct Answer

Option D is the correct answer.

Set electric force = weight: qE = mg E = mg/q = (9.11x10-31)(9.8)/(1.6x10-19) = (8.93x10-30)/(1.6x10-19) = 5.58x10-11 N/C.

Set electric force = weight: qE = mg E = mg/q = (9.11x10-31)(9.8)/(1.6x10-19) = (8.93x10-30)/(1.6x10-19) = 5.58x10-11 N/C.

Course: PHY 102

Topic: Test Compilation PHY 102 21

Type: Objective

Difficulty: Not specified

Question 1312 of 1819

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