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PHY 102 Test Compilation PHY 102 21 Objective Question
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Question

What is the electric field E experienced by a charge of magnitude 5 nC at a point where the electric force is 2x10-4 N in the x-direction? If an electron is placed in this field, what force will be exerted on it?
Options
A 6.4x10-15 N
Correct Answer
B 6.5x10-21 N
C 5.5x10-31 N
D 5.8x10-12 N
Correct Answer

Option A is the correct answer.

Detailed Explanation

Step 1 - find E: E = F/q = (2x10-4)/(5x10-9) = 4x104 N/C. Step 2 - force on an electron in that field: F = eE = (1.6x10-19)(4x104) = 6.4x10-15 N. (Direction: opposite to E, since the electron is negative.)

Hint

Step 1 - find E: E = F/q = (2x10-4)/(5x10-9) = 4x104 N/C.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 21
Type: Objective
Difficulty: Not specified
Question 1317 of 1819
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