Question Detail

PHY 102 Test Compilation PHY 102 21 Objective Question
Take CBT

Question

A uniform electric field of 4.50 kN/C passes through a rectangular surface of area 12 cm by 14 cm. The field makes an angle of 60 degrees with the normal to the surface. Determine the electric flux through the surface.
Options
A , where theta is measured from the NORMAL to the surface. A = 0.12 x 0.14 = 0.0168 m2 Phi = (4500)(0.0168)(cos 60) = (4500)(0.0168)(0.5) = 37.8 N.m2/C.
B 37.8 N.m2/C
Correct Answer
C 378 N/C
D 378 m2/C
Correct Answer

Option B is the correct answer.

Detailed Explanation

Phi = E A cos(theta), where theta is measured from the NORMAL to the surface. A = 0.12 x 0.14 = 0.0168 m2 Phi = (4500)(0.0168)(cos 60) = (4500)(0.0168)(0.5) = 37.8 N.m2/C.

Hint

Phi = E A cos(theta), where theta is measured from the NORMAL to the surface.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 21
Type: Objective
Difficulty: Not specified
Question 1327 of 1819
Previous Course Details Next