Question Detail
Question
Calculate the flux through a coil loop of area 0.45 m2 when its PLANE is inclined at an angle of 60 degrees to a magnetic field of 1.15 T.
Correct Answer
Option B is the correct answer.
Detailed Explanation
The angle is given to the PLANE, so the angle to the normal is (90 - 60) = 30 degrees. Phi = BA cos(30) = BA sin(60) = (1.15)(0.45)(0.866) = 0.448 Wb ~ 0.45 Wb.
Hint
The angle is given to the PLANE, so the angle to the normal is (90 - 60) = 30 degrees.