Question Detail

PHY 102 Test Compilation PHY 102 23 Objective Question

A 240 V a.c. source is connected across a pure 1.0 H inductor. Find the current through the inductor if the frequency of the source is 60 Hz.

A 2/pi A

Correct Answer

B 2 A

C pi/2 A

D 2*pi A

Option A is the correct answer.

XL = 2pifL = 2pi(60)(1.0) = 120pi ohms. I = V/XL = 240/(120pi) = 2/pi A.

XL = 2*pi*f*L = 2*pi(60)(1.0) = 120*pi ohms.

Course: PHY 102

Topic: Test Compilation PHY 102 23

Type: Objective

Difficulty: Not specified

Question 1383 of 1819

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