Question Detail
Question
A 2 uF capacitor is charged to 50 V and then discharged through a 1 M-ohm resistor. Find the time for the capacitor voltage to drop to 25 V.
Correct Answer
Option D is the correct answer.
Detailed Explanation
tau = RC = (1x106)(2x10-6) = 2 s. Dropping to half means t = tau x ln(2) = 2 x 0.693 = 1.386 s.
Hint
tau = RC = (1x106)(2x10-6) = 2 s.