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PHY 102 Test Compilation PHY 102 23 Objective Question
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Question

An electron, initially at rest, is accelerated through a potential difference of 600 V. What is the maximum kinetic energy of the electron?
Options
A 3.7 x 10-31 J
B 9.6 x 10-17 J
Correct Answer
C 6.0 x 102 J
D 1.4 x 104 J
Correct Answer

Option B is the correct answer.

Detailed Explanation

KE = qV = (1.6x10-19)(600) = 9.6x10-17 J.

Hint

KE = qV = (1.6x10-19)(600) = 9.6x10-17 J.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 23
Type: Objective
Difficulty: Not specified
Question 1396 of 1819
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