Question Detail

PHY 102 Test Compilation PHY 102 24 Objective Question
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Question

The resonant frequency of a circuit is 1000 kHz. If each of the capacitance and inductance is reduced by 50% with no other changes, the resonant frequency will become:
Options
A 1000 kHz
B 2000 kHz
Correct Answer
C 100.0 kHz
D 200.0 kHz
Correct Answer

Option B is the correct answer.

Detailed Explanation

f = 1/(2pisqrt(LC)). Halving both L and C quarters LC, so f doubles to 2000 kHz.

Hint

f = 1/(2*pi*sqrt(LC)).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 24
Type: Objective
Difficulty: Not specified
Question 1428 of 1819
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