Question Detail

PHY 102 Test Compilation PHY 102 25 Objective Question
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Question

An alternating voltage whose peak value is 80 volts is connected across a 60 ohm resistor. What is the value of peak current?
Options
A 1.33 A
Correct Answer
B 0.94 A
C 1.88 A
D 0.67 A
Correct Answer

Option A is the correct answer.

Detailed Explanation

I_peak = V_peak/R = 80/60 = 1.33 A.

Hint

I_peak = V_peak/R = 80/60 = 1.33 A.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 25
Type: Objective
Difficulty: Not specified
Question 1490 of 1819
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