Question Detail
Question
A battery of emf 4 V and internal resistance of 2 Ohm is joined to a resistor of 8 Ohm. Calculate the terminal p.d.
Correct Answer
Option A is the correct answer.
Detailed Explanation
I=4/10=0.4A. V=IR=(0.4)(8)=3.2V.
Hint
I=4/10=0.4A.