Question Detail
Question
The force on an electron moving in a magnetic field of strength 0.25 T is 3.2x10-14 N. Calculate the speed of the electron:
Correct Answer
Option D is the correct answer.
Detailed Explanation
v=F/(eB)=(3.2e-14)/[(1.6e-19)(0.25)]=8.0x105 m/s.
Hint
v=F/(eB)=(3.2e-14)/[(1.6e-19)(0.25)]=8.0x105 m/s.