Question Detail

PHY 102 Test Compilation PHY 102 27 Objective Question
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Question

The radius R of the circular path of an electron with mass M and charge q moving with velocity V in a magnetic field B is given as R =
Options
A MV/(qB)
Correct Answer
B Mq/(BV)
C BV/(Mq)
D qV/(MB)
Correct Answer

Option A is the correct answer.

Detailed Explanation

qVB=MV2/R => R=MV/(qB).

Hint

qVB=MV2/R => R=MV/(qB).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 27
Type: Objective
Difficulty: Not specified
Question 1567 of 1819
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