Question Detail
Question
An electron moves in a uniform magnetic field B with a velocity of 1x107 m/s. If the force on the electron is 1.6x10-12 N, calculate the magnetic field strength B.
Correct Answer
Option A is the correct answer.
Detailed Explanation
B=F/(ev)=(1.6e-12)/[(1.6e-19)(1e7)]=1.0T.
Hint
B=F/(ev)=(1.6e-12)/[(1.6e-19)(1e7)]=1.0T.