Question Detail
Question
A transformer has 200 turns in its primary coil and 600 turns in its secondary coil. If the current in the primary coil is 12.0 A, what is the current in the secondary coil?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Is=Ip x (Np/Ns)=12x(200/600)=4.0A.
Hint
Is=Ip x (Np/Ns)=12x(200/600)=4.0A.