Question Detail

PHY 102 Test Compilation PHY 102 27 Objective Question

Question

Which of the following is the correct relationship between PEAK value and R.M.S. value of an alternating signal.
Options
A peak = r.m.s. x sqrt2
Correct Answer
B r.m.s. = peak x sqrt2
C peak = r.m.s./sqrt2
D peak = sqrt2/r.m.s.
Correct Answer

Option A is the correct answer.

Detailed Explanation

Vrms=V0/sqrt2, so V0=Vrms*sqrt2.

Hint

Vrms=V0/sqrt2, so V0=Vrms*sqrt2.

Question Info