Question Detail
Question
The work function of platinum is twice that of calcium. If the minimum photon energy required to emit photoelectrons from the surface of platinum is E, then the minimum photon energy required for the surface of calcium would be:
Correct Answer
Option C is the correct answer.
Detailed Explanation
Minimum photon energy = work function. phi_Pt=2phi_Ca=E, so phi_Ca=E/2.
Hint
Minimum photon energy = work function.