Question Detail
Question
Calculate the efficiency of a motor of 240V that requires 12A to lift a 600kg load at a rate of 0.15m/s.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Pin=VI=2880W. Pout=mgv=(600)(9.8)(0.15)=882W. Efficiency=882/2880=30.6%.
Hint
Pin=VI=2880W.